What is the domain of 8/(1-1/z)-9/(1-0.5 1/z)+2 ?

The domain of 8/(1-1/z)-9/(1-0.5 1/z)+2 is z 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of 8/(1-1/z)-9/(1-0.5 1/z)+2

domain

\frac{8}{1 - \frac{1}{z}} - \frac{9}{1 - 0.5 \frac{1}{z}} + 2

z < 0 or 0 < z < \frac{1}{2} or \frac{1}{2} < z < 1 or z > 1

Interval Notation

(- \infty, 0) \cup (0, \frac{1}{2}) \cup (\frac{1}{2}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

z = 1, z = 0, z = \frac{1}{2}

The function domain

z < 0 or 0 < z < \frac{1}{2} or \frac{1}{2} < z < 1 or z > 1

What is the domain of 8/(1-1/z)-9/(1-0.5 1/z)+2 ?
The domain of 8/(1-1/z)-9/(1-0.5 1/z)+2 is z<0\lor 0<z< 1/2 \lor 1/2 <z<1\lor z>1