What is the asymptotes of f(x)=(x^2-4)/(4x-16) ?

The asymptotes of f(x)=(x^2-4)/(4x-16) is Vertical: x=4,Slant: y= 1/4 x+1

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asymptotes of f(x)=(x^2-4)/(4x-16)

asymptotes

Vertical : x = 4, Slant : y = \frac{1}{4} x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{4 x - 16} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 4}{4 x - 16} :

None

Slant Asymptotes of

\frac{x ^{2} - 4}{4 x - 16} : y = \frac{1}{4} x + 1

Vertical : x = 4, Slant : y = \frac{1}{4} x + 1

What is the asymptotes of f(x)=(x^2-4)/(4x-16) ?
The asymptotes of f(x)=(x^2-4)/(4x-16) is Vertical: x=4,Slant: y= 1/4 x+1