What is the domain of (sqrt(x^2-4))/(x+10) ?

The domain of (sqrt(x^2-4))/(x+10) is x = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of (sqrt(x^2-4))/(x+10)

domain

\frac{x ^{2} - 4}{x + 10}

x < - 10 or - 10 < x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 10) \cup (- 10, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

Find undefined (singularity) points:

x = - 10

Combine real regions and undefined points for final function domain

x < - 10 or - 10 < x \leq - 2 or x \geq 2

What is the domain of (sqrt(x^2-4))/(x+10) ?
The domain of (sqrt(x^2-4))/(x+10) is x<-10\lor-10<x<=-2\lor x>= 2