What is the domain of f(x)=-(16)/((5+t)^2) ?

The domain of f(x)=-(16)/((5+t)^2) is t -5

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domain of f(x)=-(16)/((5+t)^2)

domain

f (x) = - \frac{16}{( 5 + t ) ^{2}}

t < - 5 or t > - 5

Interval Notation

(- \infty, - 5) \cup (- 5, \infty)

Solution steps

Find undefined (singularity) points:

t = - 5

The function domain

t < - 5 or t > - 5

f (x) = x^{3} + 4 x^{2} + x - 6

f (x) = 2 (\frac{3}{x}) + 8

f (x) = \frac{x ^{2} + x}{2}

x^{2} 5 + x

5 x - 3 y = 12

What is the domain of f(x)=-(16)/((5+t)^2) ?
The domain of f(x)=-(16)/((5+t)^2) is t<-5\lor t>-5