What is the domain of f(x)= 1/((2x+3)^2) ?

The domain of f(x)= 1/((2x+3)^2) is x -3/2

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domain of f(x)= 1/((2x+3)^2)

domain

f (x) = \frac{1}{( 2 x + 3 ) ^{2}}

x < - \frac{3}{2} or x > - \frac{3}{2}

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or x > - \frac{3}{2}

What is the domain of f(x)= 1/((2x+3)^2) ?
The domain of f(x)= 1/((2x+3)^2) is x<-3/2 \lor x>-3/2