What is the critical x/(x^2+8x+15) ?

The critical x/(x^2+8x+15) is x=-sqrt(15),x=sqrt(15)

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critical x/(x^2+8x+15)

critical points

\frac{x}{x ^{2} + 8 x + 15}

x = - 15, x = 15

Solution steps

\frac{x}{x ^{2} + 8 x + 15}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 15, x = 15, x = - 5, x = - 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 8 x + 15} : x < - 5 or - 5 < x < - 3 or x > - 3

\frac{x}{x ^{2} + 8 x + 15}

is not defined at

x = - 5, x = - 3

, therefore:

x = - 15, x = 15

f (x) = \frac{x - 1}{2}

f (x) = 3 sin (\frac{1}{4} x)

\frac{x ^{2} + 3 x}{5 x ^{2} - 1}

f (x) = \frac{2 x - 5}{3 x - 9}

y = - \frac{3}{5} x + 7

What is the critical x/(x^2+8x+15) ?
The critical x/(x^2+8x+15) is x=-sqrt(15),x=sqrt(15)