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Popular >

midpoint (4,-1),(5,8)

Solution

midpoint

(4, - 1), (5, 8)

Solution

(\frac{9}{2}, \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (4, - 1), (x_{2}, y_{2}) = (5, 8)

= (\frac{5 + 4}{2}, \frac{8 - 1}{2})

Refine

= (\frac{9}{2}, \frac{7}{2})

Popular Examples

domain of f(x)=x^2-4x-3 domain

f (x) = x^{2} - 4 x - 3

domain of f(x)= 1/(2x-5)domain

f (x) = \frac{1}{2 x - 5}

domain of f(x)=(x+1)^2-9 domain

f (x) = (x + 1)^{2} - 9

domain of f(x)= 1/(2+e^{2x)}domain

f (x) = \frac{1}{2 + e ^{2 x}}

domain of f(x)=3^x+1 domain

f (x) = 3^{x} + 1

Frequently Asked Questions (FAQ)

What is the midpoint (4,-1),(5,8) ?
The midpoint (4,-1),(5,8) is (9/2 , 7/2)