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Popular >

distance (-2,5),(4,0)

Solution

distance

(- 2, 5), (4, 0)

Solution

61

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 5)

and

(4, 0)

is

= (4 - (- 2))^{2} + (0 - 5)^{2}

Simplify

= 61

Popular Examples

periodicity of f(x)=6cos(3x+pi/2)periodicity

f (x) = 6 cos (3 x + \frac{π}{2})

inflection f(x)=x^3-6x^2+4 inflection points

f (x) = x^{3} - 6 x^{2} + 4

parity v(t)=t^{2e^{-5t}}parity

v (t) = t^{2 e^{- 5 t}}

asymptotes of f(x)=(3x^2+15x)/(6x-9x^2)asymptotes

f (x) = \frac{3 x ^{2} + 15 x}{6 x - 9 x ^{2}}

inverse of x-2/x inverse

x - \frac{2}{x}

Frequently Asked Questions (FAQ)

What is the distance (-2,5),(4,0) ?
The distance (-2,5),(4,0) is square root of 61