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Popular >

distance (2.3,3.9),(2.5,3.1)

Solution

distance

(2.3, 3.9), (2.5, 3.1)

Solution

0.82462 \dots

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2.3, 3.9)

and

(2.5, 3.1)

is

= (2.5 - 2.3)^{2} + (3.1 - 3.9)^{2}

Simplify

= 0.82462 \dots

Popular Examples

domain of f(x)=sqrt(x^2-3x-40)domain

f (x) = x^{2} - 3 x - 40

domain of f(x)=x+4 domain

f (x) = x + 4

extreme f(x)=x^3-3x^2+3x-5 extreme points

f (x) = x^{3} - 3 x^{2} + 3 x - 5

midpoint (-2,0),(5,-8)midpoint

(- 2, 0), (5, - 8)

inverse of f(x)=log_{2}(x-2)inverse

f (x) = lo g_{2} (x - 2)

Frequently Asked Questions (FAQ)

What is the distance (2.3,3.9),(2.5,3.1) ?
The distance (2.3,3.9),(2.5,3.1) is 0.82462…