What is the domain of f(x)= 1/(sqrt(x^2+13x+36)) ?

The domain of f(x)= 1/(sqrt(x^2+13x+36)) is x -4

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domain of f(x)= 1/(sqrt(x^2+13x+36))

domain

f (x) = \frac{1}{x ^{2} + 13 x + 36}

x < - 9 or x > - 4

Interval Notation

(- \infty, - 9) \cup (- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 9 or x \geq - 4

Find undefined (singularity) points:

x = - 4, x = - 9

Combine real regions and undefined points for final function domain

x < - 9 or x > - 4

What is the domain of f(x)= 1/(sqrt(x^2+13x+36)) ?
The domain of f(x)= 1/(sqrt(x^2+13x+36)) is x<-9\lor x>-4