What is the domain of f(x)=(arcsin(x))/(ln(1-x^2)) ?

The domain of f(x)=(arcsin(x))/(ln(1-x^2)) is -1<x<0\lor 0<x<1

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domain of f(x)=(arcsin(x))/(ln(1-x^2))

domain

f (x) = \frac{arcsin ( x )}{ln ( 1 - x ^{2} )}

- 1 < x < 0 or 0 < x < 1

Interval Notation

(- 1, 0) \cup (0, 1)

Solution steps

Find positive values for logs:

- 1 < x < 1

Find known functions domain restrictions:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 < x < 0 or 0 < x < 1

What is the domain of f(x)=(arcsin(x))/(ln(1-x^2)) ?
The domain of f(x)=(arcsin(x))/(ln(1-x^2)) is -1<x<0\lor 0<x<1