What is the inflection f(x)=x^3-4x^2-3x+2 ?

The inflection f(x)=x^3-4x^2-3x+2 is (4/3 ,-182/27)

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inflection f(x)=x^3-4x^2-3x+2

inflection points

f (x) = x^{3} - 4 x^{2} - 3 x + 2

(\frac{4}{3}, - \frac{182}{27})

Solution steps

f^{''} (x) = 6 x - 8

Find intervals:

Concave Downward

: - \infty < x < \frac{4}{3},

Concave Upward

: \frac{4}{3} < x < \infty

Plug

x = \frac{4}{3}

into

x^{3} - 4 x^{2} - 3 x + 2 : - \frac{182}{27}

(\frac{4}{3}, - \frac{182}{27})

y = x^{2} + 6 x

f (x) = x^{2} - 12 x + 43

f (x) = x^{3} + 3 x^{2} + 3 x + 2

y = 1 + 5 sec (4 x)

\frac{1}{4} x - 3

What is the inflection f(x)=x^3-4x^2-3x+2 ?
The inflection f(x)=x^3-4x^2-3x+2 is (4/3 ,-182/27)