What is the domain of f(x)=(ln(x^2+1))/(x+3) ?

The domain of f(x)=(ln(x^2+1))/(x+3) is x -3

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domain of f(x)=(ln(x^2+1))/(x+3)

domain

f (x) = \frac{ln ( x ^{2} + 1 )}{x + 3}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > - 3

What is the domain of f(x)=(ln(x^2+1))/(x+3) ?
The domain of f(x)=(ln(x^2+1))/(x+3) is x<-3\lor x>-3