What is the inverse of f(x)=(x+3)^2+1 ?

The inverse of f(x)=(x+3)^2+1 is sqrt(x-1)-3,-sqrt(x-1)-3

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inverse of f(x)=(x+3)^2+1

inverse

f (x) = (x + 3)^{2} + 1

x - 1 - 3, - x - 1 - 3

Solution steps

y = (x + 3)^{2} + 1

Replace

x

with

y

x = (y + 3)^{2} + 1

Solve for

y, x = (y + 3)^{2} + 1

x - 1 - 3, - x - 1 - 3

f (x) = \frac{7 x}{x ^{2} + x - 2}

x^{3} - 3 x^{2} - 9 x + 10

(1, - 19), (8, - 14)

x = 8

arctan (x + 2)

What is the inverse of f(x)=(x+3)^2+1 ?
The inverse of f(x)=(x+3)^2+1 is sqrt(x-1)-3,-sqrt(x-1)-3