What is the shift f(x)=2cos(3x+pi/2) ?

The shift f(x)=2cos(3x+pi/2) is Phase:-pi/6 , Vertical:0

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shift f(x)=2cos(3x+pi/2)

shift

f (x) = 2 cos (3 x + \frac{π}{2})

Phase : - \frac{π}{6}, Vertical : 0

Solution steps

f (x) = 2 cos (3 x + \frac{π}{2})

g (B x - C) = cos (3 x + \frac{π}{2}), B = 3, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{3}

- \frac{π}{6}

The vertical shift

D

0

0

(- 3.3) (5.1)

f (x) = (x - 2)^{2} + 1

- \frac{x ^{2}}{2} - 3 x - \frac{1}{2}

f (x) = \frac{3}{x ^{2} + 4}

f (x) = \frac{2}{9} x + \frac{10}{9}

What is the shift f(x)=2cos(3x+pi/2) ?
The shift f(x)=2cos(3x+pi/2) is Phase:-pi/6 , Vertical:0