What is the range of f(x)=(x-2)/(3x+7) ?

The range of f(x)=(x-2)/(3x+7) is f(x) 1/3

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range of f(x)=(x-2)/(3x+7)

range

f (x) = \frac{x - 2}{3 x + 7}

f (x) < \frac{1}{3} or f (x) > \frac{1}{3}

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 2}{3 x + 7}

Inverse of

\frac{x - 2}{3 x + 7} : \frac{- 2 - 7 x}{3 x - 1}

\frac{- 2 - 7 x}{3 x - 1}

Find the domain of each inverse function

Domain of

\frac{- 2 - 7 x}{3 x - 1} : x < \frac{1}{3} or x > \frac{1}{3}

Combine the intervals

f (x) < \frac{1}{3} or f (x) > \frac{1}{3}

x^{2} - 7 x + 12

y = - 8 x + 2

sec (x)

f (x) = \frac{2 x}{3 x - 5}

2 sin (2 x - \frac{π}{6}) + 2

What is the range of f(x)=(x-2)/(3x+7) ?
The range of f(x)=(x-2)/(3x+7) is f(x)< 1/3 \lor f(x)> 1/3