What is the inflection f(x)=x^4-2x^2-4 ?

The inflection f(x)=x^4-2x^2-4 is (-1/(sqrt(3)),-41/9),(1/(sqrt(3)),-41/9)

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inflection f(x)=x^4-2x^2-4

inflection points

f (x) = x^{4} - 2 x^{2} - 4

(- \frac{1}{3}, - \frac{41}{9}), (\frac{1}{3}, - \frac{41}{9})

Solution steps

f^{''} (x) = 12 x^{2} - 4

Find intervals:

Concave Upward

: - \infty < x < - \frac{1}{3},

Concave Downward

: - \frac{1}{3} < x < \frac{1}{3},

Concave Upward

: \frac{1}{3} < x < \infty

Plug

x = - \frac{1}{3}

into

x^{4} - 2 x^{2} - 4 : - \frac{41}{9}

(- \frac{1}{3}, - \frac{41}{9})

Plug

x = \frac{1}{3}

into

x^{4} - 2 x^{2} - 4 : - \frac{41}{9}

(\frac{1}{3}, - \frac{41}{9})

(- \frac{1}{3}, - \frac{41}{9}), (\frac{1}{3}, - \frac{41}{9})

f (x) = \frac{1}{- x + 5}

f (x) = \frac{5 x}{x + 3}

f (x) = (x - 4)^{\frac{1}{2}}

f (x) = \frac{5}{x + 6}

f (x) = \frac{- 3}{x + 1}

What is the inflection f(x)=x^4-2x^2-4 ?
The inflection f(x)=x^4-2x^2-4 is (-1/(sqrt(3)),-41/9),(1/(sqrt(3)),-41/9)