What is the inverse of f(x)=2x^2+8x-42 ?

The inverse of f(x)=2x^2+8x-42 is (-8+sqrt(8x+400))/4 ,(-8-sqrt(8x+400))/4

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inverse of f(x)=2x^2+8x-42

inverse

f (x) = 2 x^{2} + 8 x - 42

\frac{- 8 + 8 x + 400}{4}, \frac{- 8 - 8 x + 400}{4}

Solution steps

y = 2 x^{2} + 8 x - 42

Replace

x

with

y

x = 2 y^{2} + 8 y - 42

Solve for

y, x = 2 y^{2} + 8 y - 42

\frac{- 8 + 8 x + 400}{4}, \frac{- 8 - 8 x + 400}{4}

What is the inverse of f(x)=2x^2+8x-42 ?
The inverse of f(x)=2x^2+8x-42 is (-8+sqrt(8x+400))/4 ,(-8-sqrt(8x+400))/4