What is the inverse of 9.8(T/(2pi))^2 ?

The inverse of 9.8(T/(2pi))^2 is (sqrt(5)sqrt(T)*2pi)/7 ,-(2sqrt(5)pisqrt(T))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of 9.8(T/(2pi))^2

inverse

9.8 (\frac{T}{2 π})^{2}

\frac{5 T \cdot 2 π}{7}, - \frac{2 5 π T}{7}

Solution steps

y = 9.8 (\frac{T}{2 π})^{2}

Replace

T

with

y

T = 9.8 (\frac{y}{2 π})^{2}

Solve for

y, T = 9.8 (\frac{y}{2 π})^{2}

\frac{5 T \cdot 2 π}{7}, - \frac{2 5 π T}{7}

What is the inverse of 9.8(T/(2pi))^2 ?
The inverse of 9.8(T/(2pi))^2 is (sqrt(5)sqrt(T)*2pi)/7 ,-(2sqrt(5)pisqrt(T))/7