What is the inverse of f(x)=1-4/(x^2) ?

The inverse of f(x)=1-4/(x^2) is sqrt(-4/(x-1)),-sqrt(-4/(x-1))

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inverse of f(x)=1-4/(x^2)

inverse

f (x) = 1 - \frac{4}{x ^{2}}

- \frac{4}{x - 1}, - - \frac{4}{x - 1}

Solution steps

y = 1 - \frac{4}{x ^{2}}

Replace

x

with

y

x = 1 - \frac{4}{y ^{2}}

Solve for

y, x = 1 - \frac{4}{y ^{2}}

- \frac{4}{x - 1}, - - \frac{4}{x - 1}

What is the inverse of f(x)=1-4/(x^2) ?
The inverse of f(x)=1-4/(x^2) is sqrt(-4/(x-1)),-sqrt(-4/(x-1))