What is the inverse of f(x)= 4/(x^2) ?

The inverse of f(x)= 4/(x^2) is (2sqrt(x))/x ,-(2sqrt(x))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 4/(x^2)

inverse

f (x) = \frac{4}{x ^{2}}

\frac{2 x}{x}, - \frac{2 x}{x}

Solution steps

y = \frac{4}{x ^{2}}

Replace

x

with

y

x = \frac{4}{y ^{2}}

Solve for

y, x = \frac{4}{y ^{2}}

\frac{2 x}{x}, - \frac{2 x}{x}

f (x) = x^{4} - 8 x^{2} + 9

(x + 3) e^{- 2 x}

10000 - x^{3} + 33 x^{2} + 600 x

\frac{x ( x + 4 )}{( x - 1 ) 2}

What is the inverse of f(x)= 4/(x^2) ?
The inverse of f(x)= 4/(x^2) is (2sqrt(x))/x ,-(2sqrt(x))/x