What is the inverse of f(x)=16x-4x^2 ?

The inverse of f(x)=16x-4x^2 is -(-4+sqrt(-x+16))/2 ,(sqrt(-x+16)+4)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=16x-4x^2

inverse

f (x) = 16 x - 4 x^{2}

- \frac{- 4 + - x + 16}{2}, \frac{- x + 16 + 4}{2}

Solution steps

y = 16 x - 4 x^{2}

Replace

x

with

y

x = 16 y - 4 y^{2}

Solve for

y, x = 16 y - 4 y^{2}

- \frac{- 4 + - x + 16}{2}, \frac{- x + 16 + 4}{2}

What is the inverse of f(x)=16x-4x^2 ?
The inverse of f(x)=16x-4x^2 is -(-4+sqrt(-x+16))/2 ,(sqrt(-x+16)+4)/2