What is the inverse of (x^2+3x-10)/(x^2-4) ?

The inverse of (x^2+3x-10)/(x^2-4) is (5-2x)/(x-1)

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inverse of (x^2+3x-10)/(x^2-4)

inverse

\frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

\frac{5 - 2 x}{x - 1}

Solution steps

y = \frac{x ^{2} + 3 x - 10}{x ^{2} - 4}

Replace

x

with

y

x = \frac{y ^{2} + 3 y - 10}{y ^{2} - 4}

Solve for

y, x = \frac{y ^{2} + 3 y - 10}{y ^{2} - 4}

\frac{5 - 2 x}{x - 1}

What is the inverse of (x^2+3x-10)/(x^2-4) ?
The inverse of (x^2+3x-10)/(x^2-4) is (5-2x)/(x-1)