What is the inverse of f(x)=(3y+2)(y+1)2 ?

The inverse of f(x)=(3y+2)(y+1)2 is (-5+sqrt(6y+1))/6 ,-(sqrt(6y+1)+5)/6

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inverse of f(x)=(3y+2)(y+1)2

inverse

f (x) = (3 y + 2) (y + 1) 2

\frac{- 5 + 6 y + 1}{6}, - \frac{6 y + 1 + 5}{6}

Solution steps

x = (3 y + 2) (y + 1) \cdot 2

Replace

y

with

x

y = (3 x + 2) (x + 1) \cdot 2

Solve for

x, y = (3 x + 2) (x + 1) 2

\frac{- 5 + 6 y + 1}{6}, - \frac{6 y + 1 + 5}{6}

What is the inverse of f(x)=(3y+2)(y+1)2 ?
The inverse of f(x)=(3y+2)(y+1)2 is (-5+sqrt(6y+1))/6 ,-(sqrt(6y+1)+5)/6