What is the inverse of-(1-2z^{-1})/(z^{-1)-2} ?

The inverse of-(1-2z^{-1})/(z^{-1)-2} is (2-z)/(-2z+1)

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inverse of-(1-2z^{-1})/(z^{-1)-2}

inverse

- \frac{1 - 2 z ^{- 1}}{z ^{- 1} - 2}

\frac{2 - z}{- 2 z + 1}

Solution steps

y = - \frac{1 - 2 z ^{- 1}}{z ^{- 1} - 2}

Replace

z

with

y

z = - \frac{1 - 2 y ^{- 1}}{y ^{- 1} - 2}

Solve for

y, z = - \frac{1 - 2 y ^{- 1}}{y ^{- 1} - 2}

\frac{2 - z}{- 2 z + 1}

What is the inverse of-(1-2z^{-1})/(z^{-1)-2} ?
The inverse of-(1-2z^{-1})/(z^{-1)-2} is (2-z)/(-2z+1)