What is the perpendicular x+2y=0,(1,2) ?

The perpendicular x+2y=0,(1,2) is y=2x

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perpendicular x+2y=0,(1,2)

perpendicular

x + 2 y = 0, (1, 2)

y = 2 x

Solution steps

Find the line

y = mx + b

perpendicular to

x + 2 y = 0

that passes through

(1, 2)

Find the slope of

x + 2 y = 0 : m = - \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = 2

Find the line with slope m=

2

and passing through

(1, 2) : y = 2 x

y = 2 x

f (x) = \frac{1 + e ^{- x}}{3 e ^{x}}

f (x) = \frac{x}{2 - x}

4 x^{2} - 8 x + 2

f (x) = x^{4} + 9

9 t^{4} - 12 t^{3} + 10 t^{2} - 4 t + 1