What is the inverse of f(x)=x^2+1/2 ?

The inverse of f(x)=x^2+1/2 is sqrt((2x-1)/2),-sqrt((2x-1)/2)

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inverse of f(x)=x^2+1/2

inverse

f (x) = x^{2} + \frac{1}{2}

\frac{2 x - 1}{2}, - \frac{2 x - 1}{2}

Solution steps

y = x^{2} + \frac{1}{2}

Replace

x

with

y

x = y^{2} + \frac{1}{2}

Solve for

y, x = y^{2} + \frac{1}{2}

\frac{2 x - 1}{2}, - \frac{2 x - 1}{2}

What is the inverse of f(x)=x^2+1/2 ?
The inverse of f(x)=x^2+1/2 is sqrt((2x-1)/2),-sqrt((2x-1)/2)