What is the critical f(x)=xe^{2x} ?

The critical f(x)=xe^{2x} is x=-1/2

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critical f(x)=xe^{2x}

critical points

f (x) = x e^{2 x}

x = - \frac{1}{2}

Solution steps

x e^{2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

x e^{2 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}

f (x) = x - 5

f (x) = - \frac{19}{( t + 6 ) ^{2}}

f (x) = \frac{3}{4} x + 5

2 + \frac{x ^{2}}{x ^{2} + 4}

\frac{x ^{2} - x}{x ^{3} - 4 x}