What is the domain of f(x)=(x-1)/((x+1)^2) ?

The domain of f(x)=(x-1)/((x+1)^2) is x -1

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domain of f(x)=(x-1)/((x+1)^2)

domain

f (x) = \frac{x - 1}{( x + 1 ) ^{2}}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = 3 x - 5

f (x) = \frac{4}{x ^{2} + 1}

f (x) = \frac{2}{5 + x}

\frac{x + 1}{x - 4}

f (x) = (3 - 2 x)

What is the domain of f(x)=(x-1)/((x+1)^2) ?
The domain of f(x)=(x-1)/((x+1)^2) is x<-1\lor x>-1