What is the inverse of ln(1+1/(s^2)) ?

The inverse of ln(1+1/(s^2)) is sqrt(1/(e^s-1)),-sqrt(1/(e^s-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of ln(1+1/(s^2))

inverse

ln (1 + \frac{1}{s ^{2}})

\frac{1}{e ^{s} - 1}, - \frac{1}{e ^{s} - 1}

Solution steps

y = ln (1 + \frac{1}{s ^{2}})

Replace

s

with

y

s = ln (1 + \frac{1}{y ^{2}})

Solve for

y, s = ln (1 + \frac{1}{y ^{2}})

\frac{1}{e ^{s} - 1}, - \frac{1}{e ^{s} - 1}

What is the inverse of ln(1+1/(s^2)) ?
The inverse of ln(1+1/(s^2)) is sqrt(1/(e^s-1)),-sqrt(1/(e^s-1))