What is the inverse of f(x)=-2(x-2)^2+8 ?

The inverse of f(x)=-2(x-2)^2+8 is sqrt(-(x-8)/2)+2,-sqrt(-(x-8)/2)+2

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inverse of f(x)=-2(x-2)^2+8

inverse

f (x) = - 2 (x - 2)^{2} + 8

- \frac{x - 8}{2} + 2, - - \frac{x - 8}{2} + 2

Solution steps

y = - 2 (x - 2)^{2} + 8

Replace

x

with

y

x = - 2 (y - 2)^{2} + 8

Solve for

y, x = - 2 (y - 2)^{2} + 8

- \frac{x - 8}{2} + 2, - - \frac{x - 8}{2} + 2

What is the inverse of f(x)=-2(x-2)^2+8 ?
The inverse of f(x)=-2(x-2)^2+8 is sqrt(-(x-8)/2)+2,-sqrt(-(x-8)/2)+2