What is the inverse of f(x)=(2x-4)^2,x>= 2 ?

The inverse of f(x)=(2x-4)^2,x>= 2 is (sqrt(x)+4)/2 ,(-sqrt(x)+4)/2

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inverse of f(x)=(2x-4)^2,x>= 2

inverse

f (x) = (2 x - 4)^{2}, x \geq 2

\frac{x + 4}{2}, \frac{- x + 4}{2}

Solution steps

y = (2 x - 4)^{2}

Replace

x

with

y

x = (2 y - 4)^{2}

Solve for

y, x = (2 y - 4)^{2}

\frac{x + 4}{2}, \frac{- x + 4}{2}

What is the inverse of f(x)=(2x-4)^2,x>= 2 ?
The inverse of f(x)=(2x-4)^2,x>= 2 is (sqrt(x)+4)/2 ,(-sqrt(x)+4)/2