What is the critical f(x)=(x-5)^{6/7} ?

The critical f(x)=(x-5)^{6/7} is x=5

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critical f(x)=(x-5)^{6/7}

critical points

f (x) = (x - 5)^{\frac{6}{7}}

x = 5

Solution steps

(x - 5)^{\frac{6}{7}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 5

Identify critical points not in

f (x)

domain

Domain of

(x - 5)^{\frac{6}{7}} : - \infty < x < \infty

All critical points are in domain

x = 5

f (x) = 3 x^{2} + 4 x + 1

f (x) = 10 - 3 x

f (x) = \frac{x}{6}

\frac{x ^{2}}{x ^{2} - 1}

ln (\frac{x + 1}{x - 1})