What is the inverse of f(x)=3+sqrt(x^2+4x) ?

The inverse of f(x)=3+sqrt(x^2+4x) is -2+sqrt(x^2-6x+13),-sqrt(x^2-6x+13)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=3+sqrt(x^2+4x)

inverse

f (x) = 3 + x^{2} + 4 x

- 2 + x^{2} - 6 x + 13, - x^{2} - 6 x + 13 - 2

Solution steps

y = 3 + x^{2} + 4 x

Replace

x

with

y

x = 3 + y^{2} + 4 y

Solve for

y, x = 3 + y^{2} + 4 y

- 2 + x^{2} - 6 x + 13, - x^{2} - 6 x + 13 - 2

What is the inverse of f(x)=3+sqrt(x^2+4x) ?
The inverse of f(x)=3+sqrt(x^2+4x) is -2+sqrt(x^2-6x+13),-sqrt(x^2-6x+13)-2