What is the critical f(x)=8sqrt(x)-6x ?

The critical f(x)=8sqrt(x)-6x is x=0,x= 4/9

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critical f(x)=8sqrt(x)-6x

critical points

f (x) = 8 x - 6 x

x = 0, x = \frac{4}{9}

Solution steps

8 x - 6 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{4}{9}, x = 0

Identify critical points not in

f (x)

domain

Domain of

8 x - 6 x : x \geq 0

All critical points are in domain

x = 0, x = \frac{4}{9}

f (x) = 2 - \frac{1 + x}{x}

3^{2 x + 4} + 3

f (x) = 3 - 2 x + 1

(y - 8) = 7 (x - 10)

\frac{2 x}{12 - x ^{2} - 25}

What is the critical f(x)=8sqrt(x)-6x ?
The critical f(x)=8sqrt(x)-6x is x=0,x= 4/9