What is the inverse of f(x)=(x^2+6x)^{0.5} ?

The inverse of f(x)=(x^2+6x)^{0.5} is -3+(x^2+9)^{1/2},-(x^2+9)^{1/2}-3

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inverse of f(x)=(x^2+6x)^{0.5}

inverse

f (x) = (x^{2} + 6 x)^{0.5}

- 3 + (x^{2} + 9)^{\frac{1}{2}}, - (x^{2} + 9)^{\frac{1}{2}} - 3

Solution steps

y = (x^{2} + 6 x)^{0.5}

Replace

x

with

y

x = (y^{2} + 6 y)^{0.5}

Solve for

y, x = (y^{2} + 6 y)^{0.5}

- 3 + (x^{2} + 9)^{\frac{1}{2}}, - (x^{2} + 9)^{\frac{1}{2}} - 3

What is the inverse of f(x)=(x^2+6x)^{0.5} ?
The inverse of f(x)=(x^2+6x)^{0.5} is -3+(x^2+9)^{1/2},-(x^2+9)^{1/2}-3