What is the inverse of f(x)=((x-9)^{1/3})/5 ?

The inverse of f(x)=((x-9)^{1/3})/5 is 125x^3+9

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inverse of f(x)=((x-9)^{1/3})/5

inverse

f (x) = \frac{( x - 9 ) ^{\frac{1}{3}}}{5}

125 x^{3} + 9

Solution steps

y = \frac{( x - 9 ) ^{\frac{1}{3}}}{5}

Replace

x

with

y

x = \frac{( y - 9 ) ^{\frac{1}{3}}}{5}

Solve for

y, x = \frac{( y - 9 ) ^{\frac{1}{3}}}{5}

125 x^{3} + 9

What is the inverse of f(x)=((x-9)^{1/3})/5 ?
The inverse of f(x)=((x-9)^{1/3})/5 is 125x^3+9