What is the inverse of f(x)=2x^2+4x+3 ?

The inverse of f(x)=2x^2+4x+3 is (-4+sqrt(8x-8))/4 ,(-4-sqrt(8x-8))/4

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inverse of f(x)=2x^2+4x+3

inverse

f (x) = 2 x^{2} + 4 x + 3

\frac{- 4 + 8 x - 8}{4}, \frac{- 4 - 8 x - 8}{4}

Solution steps

y = 2 x^{2} + 4 x + 3

Replace

x

with

y

x = 2 y^{2} + 4 y + 3

Solve for

y, x = 2 y^{2} + 4 y + 3

\frac{- 4 + 8 x - 8}{4}, \frac{- 4 - 8 x - 8}{4}

What is the inverse of f(x)=2x^2+4x+3 ?
The inverse of f(x)=2x^2+4x+3 is (-4+sqrt(8x-8))/4 ,(-4-sqrt(8x-8))/4