What is the inverse of f(x)=4(x-3)^2+2 ?

The inverse of f(x)=4(x-3)^2+2 is (sqrt(x-2))/2+3,-(sqrt(x-2))/2+3

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inverse of f(x)=4(x-3)^2+2

inverse

f (x) = 4 (x - 3)^{2} + 2

\frac{x - 2}{2} + 3, - \frac{x - 2}{2} + 3

Solution steps

y = 4 (x - 3)^{2} + 2

Replace

x

with

y

x = 4 (y - 3)^{2} + 2

Solve for

y, x = 4 (y - 3)^{2} + 2

\frac{x - 2}{2} + 3, - \frac{x - 2}{2} + 3

What is the inverse of f(x)=4(x-3)^2+2 ?
The inverse of f(x)=4(x-3)^2+2 is (sqrt(x-2))/2+3,-(sqrt(x-2))/2+3