What is the inverse of (e^y-e^{-y})/2 ?

The inverse of (e^y-e^{-y})/2 is ln(y+sqrt(y^2+1)),ln(y-sqrt(y^2+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of (e^y-e^{-y})/2

inverse

\frac{e ^{y} - e ^{- y}}{2}

ln (y + y^{2} + 1), ln (y - y^{2} + 1)

Solution steps

y = \frac{e ^{y} - e ^{- y}}{2}

Replace

y

with

y

y = \frac{e ^{y} - e ^{- y}}{2}

Solve for

y, y = \frac{e ^{y} - e ^{- y}}{2}

ln (y + y^{2} + 1), ln (y - y^{2} + 1)

What is the inverse of (e^y-e^{-y})/2 ?
The inverse of (e^y-e^{-y})/2 is ln(y+sqrt(y^2+1)),ln(y-sqrt(y^2+1))