What is the domain of f(x)=2-sqrt(13-e^{4t)} ?

The domain of f(x)=2-sqrt(13-e^{4t)} is t<= (ln(13))/4

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domain of f(x)=2-sqrt(13-e^{4t)}

domain

f (x) = 2 - 13 - e^{4 t}

t \leq \frac{ln ( 13 )}{4}

Interval Notation

(- \infty, \frac{ln ( 13 )}{4}]

Solution steps

Find non-negative values for radicals:

t \leq \frac{ln ( 13 )}{4}

The function domain

t \leq \frac{ln ( 13 )}{4}

f (x) = x^{2}, x \geq 0

ln (4) + ln (x)

f (x) = 2 x^{2} - 4 x - 6

(f (x) \circ g (x)), f (x) = x^{2}, g (x) = x + 1

f (x) = 4 x + 1

What is the domain of f(x)=2-sqrt(13-e^{4t)} ?
The domain of f(x)=2-sqrt(13-e^{4t)} is t<= (ln(13))/4