What is the inverse of f(x)=(log_{10}(x-5))/2 ?

The inverse of f(x)=(log_{10}(x-5))/2 is 100^x+5

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inverse of f(x)=(log_{10}(x-5))/2

inverse

f (x) = \frac{lo g _{10} ( x - 5 )}{2}

10 0^{x} + 5

Solution steps

y = \frac{lo g _{10} ( x - 5 )}{2}

Replace

x

with

y

x = \frac{lo g _{10} ( y - 5 )}{2}

Solve for

y, x = \frac{lo g _{10} ( y - 5 )}{2}

10 0^{x} + 5

What is the inverse of f(x)=(log_{10}(x-5))/2 ?
The inverse of f(x)=(log_{10}(x-5))/2 is 100^x+5