What is the inverse of 4sin(2x+5)-7 ?

The inverse of 4sin(2x+5)-7 is (arcsin((x+7)/4)-5)/(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of 4sin(2x+5)-7

inverse

4 sin (2 x + 5) - 7

\frac{arcsin ( \frac{x + 7}{4} ) - 5}{2}

Solution steps

Solve for

sin (2 x + 5), y = 4 sin (2 x + 5) - 7

sin (2 x + 5) = \frac{y + 7}{4}

sin (a) = b \Rightarrow a = arcsin (b)

2 x + 5 = arcsin (\frac{y + 7}{4})

Solve for

x, 2 x + 5 = arcsin (\frac{y + 7}{4})

\frac{arcsin ( \frac{y + 7}{4} ) - 5}{2}

Substitute

y = x

\frac{arcsin ( \frac{x + 7}{4} ) - 5}{2}

What is the inverse of 4sin(2x+5)-7 ?
The inverse of 4sin(2x+5)-7 is (arcsin((x+7)/4)-5)/(2)