What is the inverse of f(x)=160t-16t^2 ?

The inverse of f(x)=160t-16t^2 is -(-20+sqrt(-t+400))/4 ,(sqrt(-t+400)+20)/4

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inverse of f(x)=160t-16t^2

inverse

f (x) = 160 t - 16 t^{2}

- \frac{- 20 + - t + 400}{4}, \frac{- t + 400 + 20}{4}

Solution steps

x = 160 t - 16 t^{2}

Replace

t

with

x

t = 160 x - 16 x^{2}

Solve for

x, t = 160 x - 16 x^{2}

- \frac{- 20 + - t + 400}{4}, \frac{- t + 400 + 20}{4}

3 x - 4 y = - 8

4 - x^{2}

- \frac{1}{6} x^{2} + 200 x

y = 2 (x - 4) (x + 2)

\frac{1}{x ^{2} + 1}

What is the inverse of f(x)=160t-16t^2 ?
The inverse of f(x)=160t-16t^2 is -(-20+sqrt(-t+400))/4 ,(sqrt(-t+400)+20)/4