What is the domain of f(x)=sqrt(3x+7) ?

The domain of f(x)=sqrt(3x+7) is x>=-7/3

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domain of f(x)=sqrt(3x+7)

domain

f (x) = 3 x + 7

x \geq - \frac{7}{3}

Interval Notation

[- \frac{7}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{7}{3}

The function domain

x \geq - \frac{7}{3}

f (x) = \frac{1}{x - 6}

5 x - y = 12

f (x) = - \frac{4}{3} x - 8

f (x) = \frac{- 6 x}{x ^{2} + 3}

x = 4 y

What is the domain of f(x)=sqrt(3x+7) ?
The domain of f(x)=sqrt(3x+7) is x>=-7/3