What is the extreme f(x)=x^4-242x^2-14641 ?

The extreme f(x)=x^4-242x^2-14641 is Minimum(-11,-29282),Maximum(0,-14641),Minimum(11,-29282)

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extreme f(x)=x^4-242x^2-14641

extreme points

f (x) = x^{4} - 242 x^{2} - 14641

Minimum (- 11, - 29282), Maximum (0, - 14641), Minimum (11, - 29282)

Solution steps

f^{'} (x) = 4 x^{3} - 484 x

Find intervals:

Decreasing

: - \infty < x < - 11,

Increasing

: - 11 < x < 0,

Decreasing

: 0 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = - 11

into

x^{4} - 242 x^{2} - 14641 : - 29282

Minimum (- 11, - 29282)

Plug

x = 0

into

x^{4} - 242 x^{2} - 14641 : - 14641

Maximum (0, - 14641)

Plug

x = 11

into

x^{4} - 242 x^{2} - 14641 : - 29282

Minimum (11, - 29282)

Minimum (- 11, - 29282), Maximum (0, - 14641), Minimum (11, - 29282)

f (x) = \frac{( x ^{3} + 3 x ^{2} )}{( 7 x ^{2} - 2 )}

f (x) = x

y = - 3

\frac{5}{5 + x}

y = x^{3} - x^{2} - x + 1

What is the extreme f(x)=x^4-242x^2-14641 ?
The extreme f(x)=x^4-242x^2-14641 is Minimum(-11,-29282),Maximum(0,-14641),Minimum(11,-29282)