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Popular Functions >

range of f(x)=1-(x-2)^2

Solution

range

Solution

f (x) \leq 1

+1

Interval Notation

Solution steps

Vertex of

1 - (x - 2)^{2} :

Maximum

(2, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (2, 1)

f (x) \leq 1

Graph

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Frequently Asked Questions (FAQ)

What is the range of f(x)=1-(x-2)^2 ?
The range of f(x)=1-(x-2)^2 is f(x)<= 1