What is the inverse of f(x)=2(x-2)^2-3 ?

The inverse of f(x)=2(x-2)^2-3 is sqrt((x+3)/2)+2,-sqrt((x+3)/2)+2

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inverse of f(x)=2(x-2)^2-3

inverse

f (x) = 2 (x - 2)^{2} - 3

\frac{x + 3}{2} + 2, - \frac{x + 3}{2} + 2

Solution steps

y = 2 (x - 2)^{2} - 3

Replace

x

with

y

x = 2 (y - 2)^{2} - 3

Solve for

y, x = 2 (y - 2)^{2} - 3

\frac{x + 3}{2} + 2, - \frac{x + 3}{2} + 2

(0) (8.4)

f (x) = 0.5 x + 1

f (x) = \frac{1}{ln ( x + 3 )}

f (x) = x [n] = 5 sin (0.2 πn)

f (x) = x^{3} - 2

What is the inverse of f(x)=2(x-2)^2-3 ?
The inverse of f(x)=2(x-2)^2-3 is sqrt((x+3)/2)+2,-sqrt((x+3)/2)+2