What is the vertices y=(x-3)(x+3) ?

The vertices y=(x-3)(x+3) is Minimum (0,-9)

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vertices y=(x-3)(x+3)

vertices

Minimum (0, - 9)

Solution steps

y = (x - 3) (x + 3)

y = (x - 3) (x + 3)

The parabola parameters are:

a = 1, m = 3, n = - 3

x_{v} = \frac{m + n}{2}

x_{v} = \frac{3 + ( - 3 )}{2}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = - 9

Therefore the parabola vertex is

(0, - 9)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (0, - 9)