What is the domain of G(t)=-(21)/((4+t)^2) ?

The domain of G(t)=-(21)/((4+t)^2) is t -4

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domain of G(t)=-(21)/((4+t)^2)

domain

G (t) = - \frac{21}{( 4 + t ) ^{2}}

t < - 4 or t > - 4

Interval Notation

(- \infty, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

t = - 4

The function domain

t < - 4 or t > - 4

(2, 3), (7, 4)

5 x - 4 y = - 20

f (x) = \frac{1}{4} x - \frac{1}{3}

x^{3} + x^{2}

\frac{π}{4} - arctan (3 x - 2)

What is the domain of G(t)=-(21)/((4+t)^2) ?
The domain of G(t)=-(21)/((4+t)^2) is t<-4\lor t>-4